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Home/ Questions/Q 3238484
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T17:51:32+00:00 2026-05-17T17:51:32+00:00

Got these examples I would like to understand but they are in Scheme. I

  • 0

Got these examples I would like to understand but they are in Scheme. I would like them in Clojure 😀

Example 1 – counting the length of a list


(define length
  (lambda (ll)
    (cond
      ((null? ll) 0)
      (#t (add1
        (length (cdr ll)))))))

Exemple 2 – square each element of a list


(define squares
  (lambda (li)
    (cond
      ((null? li) ())
      (#t (cons
            (* (char li) (char li))
            (squares(cdr
    li)))))))

Example 3 – the “map” function (as in map/reduce)


(define map (lambda (func lst)
  (cond ((null? lst) ())
        (#t (cons (func (car lst))
              (map func (cdr lst)))))))

Curried “map”


(define map2
  (lambda (func)
    (lambda (lst)
      (cond ((null? lst) ())
        (#t (cons (func (car lst))
              ((map2 func) (cdr lst)))))))

Motivation

The examples are from a presentation on Functional Programming someone else might be interested it: Functional Languages 101: What’s All the Fuss About?

Once you submit an answer, I’d like your agreement to post it as a comment at that presentation for Clojure people to understand the original code

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T17:51:33+00:00Added an answer on May 17, 2026 at 5:51 pm

    Length of a list:

    (defn my-length [lst]
        (loop [len 0 x lst]
            (if (empty? x)
                len
                (recur (+ 1 len) (rest x)))))
    
    user=> (my-length '(1))
    1
    user=> (my-length '(1 2 3 4))
    4
    user=> (my-length '())
    0
    

    Square each element of a list:

    (defn squares [lst]
        (loop [sqrs '() x lst]
           (if (empty? x)
               (reverse sqrs)
               (recur (cons (* (first x) (first x)) sqrs) (rest x)))))
    
    user=> (squares '(1 2 3 4))
    (1 4 9 16)
    

    Map:

    (defn my-map [func lst]
        (loop [res '() x lst]
           (if (empty? x) 
               (reverse res) 
               (recur (cons (func (first x)) res) (rest x)))))
    
    user=> (my-map (fn [x] (* x 2)) '(1 2 3))
    (2 4 6)
    

    Map2:

    See nickik’s solution.

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