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Home/ Questions/Q 522795
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:23:29+00:00 2026-05-13T08:23:29+00:00

Greetings, I have file with the following strings: string.Format({0},{1}, Having \Two\ On The Same

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Greetings, I have file with the following strings:

string.Format("{0},{1}", "Having \"Two\" On The Same Line".Localize(), "Is Tricky For regex".Localize());

my goal is to get a match set with the two strings:

  • Having \”Two\” On The Same Line
  • Is Tricky For regex

My current regex looks like this:

private Regex CSharpShortRegex = new Regex("\"(?<constant>[^\"]+?)\".Localize\\(\\)");

My problem is with the escaped quotes in the first line I end up stopping at the quote and I get:

  • On The Same Line
  • Is Tricky For This Style Too

however attempting to ignore the escaped quotes is not working out because it makes the Regex greedy and I get

  • Having \”Two\” On The Same Line”.Localize(), “Is Tricky For regex”

We seem to be caught between maximum and minimum munge. Is there any hope? I have some backup plans. Can you Regex backwards? that would make it easier because I can start with the “()ezilacoL.”

EDIT:
To clarify. This is my lone edge case. Most of the time the string sits alone like:

var myString = "Hot Patootie".Localize()
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  1. Editorial Team
    Editorial Team
    2026-05-13T08:23:29+00:00Added an answer on May 13, 2026 at 8:23 am

    This one works for me:

    \"((?:[^\\"]|(?:\\\"))*)\"\.Localize\(\)
    

    Tested on http://www.regexplanet.com/simple/index.html against a number of strings with various escaped quotes.

    Looks like most of us who answered this one had the same rough idea, so let me explain the approach (comments after #s):

    \"             # We're looking for a string delimited by quotation marks
    (              # Capture the contents of the quotation marks
      (?:          #   Start a non-capturing group
        [^\\"]     #     Either read a character that isn't a quote or a slash
        |(?:\\\")  #     Or read in a slash followed by a quote.
      )*           #   Keep reading
    )              # End the capturing group
    \"             # The string literal ends in a quotation mark
    \.Localize\(\) # and ends with the literal '.Localize()', escaping ., ( and )
    

    For C# you’ll need to escape the slashes twice (messy):

    \"((?:[^\\\\\"]|(?:\\\\\"))*)\"\\.Localize\\(\\)
    

    Mark correctly points out that this one doesn’t match escaped characters other than quotation marks. So here’s a better version:

    \"((?:[^\\"]|(?:\\")|(?:\\.))*)\"\.Localize\(\)
    

    And its slashed-up equivalent:

    \"((?:[^\\\\\"]|(?:\\\\\")|(?:\\\\.))*)\"\\.Localize\\(\\)
    

    Works the same way, except it has a special case that if encounters a slash but it can’t match \", it just consumes the slash and the following character and moves on.


    Thinking about it, it’s better to just consume two characters at every slash, which is effectively Mark’s answer so I won’t repeat it.

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