Question

Hail to the fellow programmers and query writers,

I have this beautiful query

SELECT ID, [1] AS coL1, [15] AS coL2, [2] AS coL3, [16] AS coL4, [12] AS coL5
FROM MY_TABLE
PIVOT (sum(INT_VALUE) FOR FUND_CODE IN ([1],[2],[15],[16],[12])) AS p
--GROUP BY ID, [1] , [15]  , [2] , [16] , [12] 
ORDER BY ID ASC

That returns me data like this:

10001      182       NULL      NULL      NULL
10001      NULL      81        NULL      NULL
10001      NULL      NULL      182       NULL
10001      NULL      NULL      NULL      81
10002      165       NULL      NULL      NULL
10002      NULL      73        NULL      NULL
10002      NULL      NULL      165       NULL
10002      NULL      NULL      NULL      73

The 10001 and 10002 are two primary keys, and I’d like to show my data like this:

10001      182       81      182      81
10002      165       73      165      73

I tried this commented GROUP BY to no avail.
Any hints? Does it involve COALESCE?

Answer 1

Just in CASE…

SELECT ID,
SUM(CASE WHEN FUND_CODE = 1 THEN VR_MOVIMENTACAO_QUOTA ELSE 0 END) coL1,
SUM(CASE WHEN FUND_CODE = 15 THEN VR_MOVIMENTACAO_QUOTA ELSE 0 END) coL2,
SUM(CASE WHEN FUND_CODE = 2 THEN VR_MOVIMENTACAO_QUOTA ELSE 0 END) coL3,
SUM(CASE WHEN FUND_CODE = 16 THEN VR_MOVIMENTACAO_QUOTA ELSE 0 END) coL4,
SUM(CASE WHEN FUND_CODE = 12 THEN VR_MOVIMENTACAO_QUOTA ELSE 0 END) coL5

FROM MY_TABLE
GROUP BY ID