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Home/ Questions/Q 8225747
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T15:31:10+00:00 2026-06-07T15:31:10+00:00

Has anyone found that their javascript doesnt work, but when they step through the

  • 0

Has anyone found that their javascript doesnt work, but when they step through the code it works fine ?

    var cookie = getCookie('lusr');
var username = cookie;
if(!cookie){
    $("#UserNav").load("loginform.html");
    $("#loginbtn").click( function(){
        var username = $("#usernametxt").val();
        var password = $("#passwordtxt").val();
        login(username,password);
    });
}else{
    $("#UserNav").load("user.htm");
    $("#WelcomeUser").text("Welcome "+ username);
}

My issue occurs on this line :

        $("#WelcomeUser").text("Welcome "+ username);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T15:31:13+00:00Added an answer on June 7, 2026 at 3:31 pm

    That’s because load() is asynchronous: it returns right away, performs its work in the background, then calls a user-provided function when its task is complete. The stepping delay gives you the illusion that the function is synchronous and performs all its work before returning.

    Therefore, you should pass a callback function to load() and perform your subsequent work inside that callback:

    var cookie = getCookie("lusr");
    if(!cookie) {
        $("#UserNav").load("loginform.html", function() {
            $("#loginbtn").click(function() {
                var username = $("#usernametxt").val();
                var password = $("#passwordtxt").val();
                login(username, password);
            });
        });
    } else {
        $("#UserNav").load("user.htm", function() {
            $("#WelcomeUser").text("Welcome " + cookie);
        });
    }
    
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