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Editorial Team
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Asked: 2026-06-15T00:33:57+00:00

Has: IEnumerable<int> oldValues; // Example: [1, 2, 3, 4] IEnumerable<int> newValues; // Example: [3,

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Has:

IEnumerable<int> oldValues; // Example: [1, 2, 3, 4]
IEnumerable<int> newValues; // Example: [3, 4, 5, 6]

Need:

IEnumerable<int> removedValues; // Example: [1, 2]
IEnumerable<int> addedValues;   // Example: [5, 6]

Any ideas of nice LINQ solution?

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1 Answer

  1. Editorial Team

    You need Enumerable.Except – this method returns those elements in first sequence that do not appear in second sequence. 

    IEnumerable<int> removedValued = oldValues.Except(newValues);
IEnumerable<int> addedValues = newValues.Except(oldValues);
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