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Home/ Questions/Q 3391112
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T03:46:05+00:00 2026-05-18T03:46:05+00:00

Hashtable<String, Hashtable<String, HashSet<String>>> test = new Hashtable<String, Hashtable<String, HashSet<String>>>(); test.put(1, new Hashtable<String, HashSet<String>>()); Hashtable<String,

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Hashtable<String, Hashtable<String, HashSet<String>>> test = 
        new Hashtable<String, Hashtable<String, HashSet<String>>>();
test.put("1", new Hashtable<String, HashSet<String>>());
Hashtable<String, HashSet<String>> actual = test.get("1");
actual.put("3", new HashSet<String>());
//test.put("1", actual);
HashSet<String> expected = test.get("1").get("3");
if ( expected == null ) {
 System.out.println("DIE");      
} 

Based on the code above, I thought DIE would be printed out. But apparently, actual is a reference to the object inside test still. I was under the impression that I had to “put” back actual into test (shown by the line that had been commented out). Is there authoritative documentation on whether actual is a reference or not?

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  1. Editorial Team
    Editorial Team
    2026-05-18T03:46:05+00:00Added an answer on May 18, 2026 at 3:46 am

    Objects are always passed as a reference in Java. From chapter 4 of JLS:

    The reference types are class types, interface types, and array types. … The reference values (often just references) are pointers to these objects.

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