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Home/ Questions/Q 7669233
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T15:32:56+00:00 2026-05-31T15:32:56+00:00

hash(value1 & value2 & salt) hash(hash(value1 & value2) & salt) hash(hash(value1 & value2) &

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hash(value1 & value2 & salt)
hash(hash(value1 & value2) & salt)
hash(hash(value1 & value2) & hash(salt))
hash(hash(value1 & salt) & hash(value2 & salt))
hash(hash(value1 & salt1) & hash(value2 & salt2))
hash(value1 & salt1 &value2 & salt2)
hash(value1 & salt1) and hash(value2 & salt2)  '2 separate hashes for each input

In an application where 2 ‘passwords’ are needed to access a specific function (for whatever reason you want) and the salt(s) are large random strings. What would be the best way of getting a final hash to store? (not necessarily 1 of the above)

Is it ‘better’ to have the outside/final hash algorithm different to the inner ones?

Side question: is a salt mainly for making short, crappy user pw’s more secure from brute force attacks? So if the pw was large (say the ByteArray of an image file) would a salt add any real purpose? Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-31T15:32:57+00:00Added an answer on May 31, 2026 at 3:32 pm

    Assuming & means concatenation, the safest is:

    hash(value1 & delim & value2 & delim & salt)
    

    …where delim is a delimiter that cannot appear in any of the other strings. It doesn’t matter which order value1, value2 and salt appear in.

    The delimeter prevents aliasing, e.g., (value1, value2) = ('fail', 'stone') vs (value1, value2) = ('fails', 'tone').

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