Question

Have a look at the following code:

try
{
    Parallel.Foreach(...)//50 Thread For Each Time
    {
        string str = MyMethod();
    }
}
catch
{

}
public string MyMethod()
{
     CookieContainer cookieJar = new CookieContainer();

     // Some code that throws an exception.
}

How can I pass cookieJar to the catch block?

Note:
For some reason I can’t use global variables. I’m using Parallel.ForEach in try And I can’t control global variables inside MyMethod because of parallel changes.

Answer 1

You could catch the exception in MyMethod and rethrow a new exception that will hold the CookieContainer object:

try
{
    Parallel.ForEach(...)
    {
        string str = MyMethod();
    }
}
catch (AggregateException ae)
{
    // This is where you can choose which exceptions to handle.
    foreach (var ex in ae.InnerExceptions.OfType<MyCookieException>())
    {
        CookieContainer c = ex.CookieContainer;

        // Do stuff with CookieContainer.
    }
}

public string MyMethod()
{
     CookieContainer cookieJar = new CookieContainer();
     try
     {
         // Some code that throws an exception
     }
     catch (Exception ex)
     {
         throw new MyCookieException(ex, cookieJar);
     }
}