Question

have a php code like this,going to convert it in to C#.

function isValid($n){
if (preg_match("/\d+/",$n) > 0 && $n<1000) {
    return true;
}
return false;
}

Here is my try,BUT error shown Error is “expected class, delegate, enum, interface or struct error C#”

public string IsValidate(string Item)
{
    string Result = Item;
   try
{
Result = System.Text.RegularExpressions.Regex.Replace(InputTxt, @"(\\)([\000\010\011\012\015\032\042\047\134\140])", "$2");
}
catch(Exception ex)
{
console.WriteLine(ex.Message)
}
return Result;
}

What is the error,Is there any other way to implement this better than my try ?
i got this snippet from here code

Answer 1

You haven’t define this method inside a class/struct that is why you are getting this error. You may define this method inside a class.

public class MyValidator
    {
        public string IsValidate(string Item)
        {
          //Your code here
        }

    }

Later you can use it like:

MyValidator validator = new MyValidator();
validator.IsValid("Your string");

Also you are missing semicolon at the end of the Console.Write statement, plus ‘c’ for Console should be in uppercase

Edit:
Since in your php code, it looks like you are trying to see if the string passed is an integer and it is less than 1000, you may use the int.TryParse like the following:

public class MyValidator
{
    public bool IsValidate(string Item)
    {
        string Result = Item;
        int val;
        if (int.TryParse(Item, out val) && val > 0 && val < 1000)
        {
            return true;
        }
        else
        {
            return false;
        }

    }
}

In you main method you can do:

 static void Main()
        {
            MyValidator validator = new MyValidator();
            Console.WriteLine(validator.IsValidate("asdf123")); // This will print false
            Console.WriteLine(validator.IsValidate("999")); //This will print true
            Console.WriteLine(validator.IsValidate("1001")); //This will print false
         }