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Home/ Questions/Q 8683419
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T22:02:29+00:00 2026-06-12T22:02:29+00:00

have built a functional form with PHP however I have a checkbox with 5

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have built a functional form with PHP however I have a checkbox with 5 options (more than 1 can be selected) however only 1 option is showing up in the email.

HTML:

<label class="radio"><input type="checkbox" name="service" value="Web Design" />Web Design</label>
<label class="radio"><input type="checkbox" name="service" value="Graphic Design" />Graphic Design</label>
<label class="radio"><input type="checkbox" name="service" value="Brand Identity" />Brand Identity</label>
<label class="radio"><input type="checkbox" name="service" value="Online Marketing" />Online Marketing</label>
<label class="radio"><input type="checkbox" name="service" value="Other" />Other</label>

PHP: ($service)

<?php
$name = $_POST['name'];
$email = $_POST['email'];
$phone = $_POST['phone'];
$website = $_POST['website'];
$service = $_POST['service'];
$description = $_POST['description'];
$inspiration = $_POST['inspiration'];
$budget = $_POST['budget'];
$deadline = $_POST['deadline'];
$formcontent=" From: $name \n Email: $email \n Phone: $phone \n Website: $website \n\n service: $service \n budget: $budget \n deadline: $deadline \n\n description: $description \n\n inspiration: $inspiration ";
$recipient = "myemail@gmail.com";
$subject = "Contact form";
$mailheader = "From: $email \r\n";
mail($recipient, $subject, $formcontent, $mailheader) or die("Error!");
echo "Thank You, your information has been received.";
?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T22:02:31+00:00Added an answer on June 12, 2026 at 10:02 pm

    If you have multiple elements with the same name then you will only be able to read one of them unless you use the array syntax [] e.g. name=service[] then you will receive $_POST[‘service’] as an array containing all your services. You can use implode to convert it to a string.

    $service = implode(' ', $_POST['service']);
    
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