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Home/ Questions/Q 4081298
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T18:02:34+00:00 2026-05-20T18:02:34+00:00

Have following String built SQL query: StringBuilder querySelect = new StringBuilder(select * from messages

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Have following String built SQL query:

    StringBuilder querySelect = new StringBuilder("select * from messages ");
    StringBuilder queryWhere = new StringBuilder("where msg_id=?");

        if (fileRSVO.getFileName()!= null){
            queryWhere.append("and descr LIKE %?% ");
        }
querySelect.append(queryWhere);

    List<Map<String, Object>> list = getJdbcTemplate().queryForList(querySelect.toString(), params.toArray()); 
    ...

The problem is in this part:

queryWhere.append("and descr LIKE %?% ")

LIKE doesn’t work.
Checked in debug – it’s added to all query.
Should it be single quoted or some other trick?

thanks.

EDITED

tried single quotes:queryWhere.append("and descr LIKE '%?%' ")
doesn’t work

here is debug string:

select * from messages where msg_id=? and descr LIKE '%?%' 
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  1. Editorial Team
    Editorial Team
    2026-05-20T18:02:35+00:00Added an answer on May 20, 2026 at 6:02 pm

    ? is not a placeholder for textual substitution, it’s a parameter (i.e. it’s like variable in Java), therefore it should be treated as a separate token. This should work, but perhaps not in all databases:

    queryWhere.append("and descr LIKE ('%' || ? || '%')"); 
    

    Alternativelty you can pass %s as parts of parameter value, as suggested by Justin Muller.

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