Question

Have just come across a problem where I believe this is the solution.

At the moment I have the following code:

function siteUsers()
{
    global $database;
    $q = "SELECT username, id FROM ".TBL_USERS."";
    return mysql_query($q, $this->connection);
}

function generateUserArray() 
{
    $u = array();
    $i = array();
    $result = $this->siteUsers();
    while( $row=mysql_fetch_assoc($result)) 
    {
        $u[] = $row['username'];
        $i[] = $row['id'];
    }
    return $u, $i;
}

As you can see, when I then go onto use foreach, the $u and $i get split apart.
Is there anyway that I could keep them together?

foreach ($u as $username) {
    echo"<option value='$i'>$username</option>";
}

What I need it the option value to be the id and the visual value to be the username.
Is this possible?

Answer 1

Use an associative array linking the ID to the username. I’m assuming here the IDs are unique.

$users = array();
while( $row=mysql_fetch_assoc($result)) 
{
    $users[$row['id']] = $row['username'];
}
return $users;

Then:

foreach ($users as $id => $username)
{
    echo "<option value='$id'>$username</option>";
}