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Home/ Questions/Q 7458741
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T13:29:25+00:00 2026-05-29T13:29:25+00:00

have some headers like: HTTP/1.1 100 Continue HTTP/1.1 302 Found HTTP/1.1 200 OK HTTP/1.1

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have some headers like:

HTTP/1.1 100 Continue
HTTP/1.1 302 Found
HTTP/1.1 200 OK
HTTP/1.1 400 Not Found

so, I need to get 2 parts:

[200] => [OK]
[400] => [Not Found]

I need a way to use preg_match_all and get those values, but need to preserve the spaces at Not Found

have this code:

preg_match_all( '/([0-9]{3}) ([A-Za-z0-9+]*)/', $headers, $matches );

Works with 1-3 example headers.

Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T13:29:26+00:00Added an answer on May 29, 2026 at 1:29 pm

    For the single line and for the text in general

    $str = "HTTP/1.1 100 Continue
    HTTP/1.1 302 Found
    HTTP/1.1 200 OK
    HTTP/1.1 400 Not Found";
    
    // for the values in the string, one on each line
    preg_match_all('#(\d{3})\s+([\w\s]+)$#m', $str, $matches);
    var_dump($matches);  // captures a new line symbol if exists
    
    // for single value in the string
    $str = "HTTP/1.1 400 Not Found";
    preg_match('#(\d{3})\s+([\w\s]+)$#', $str, $matches);
    var_dump($matches);
    

    So, do you have each header on a new line or not?

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