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Home/ Questions/Q 9028749
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T07:04:11+00:00 2026-06-16T07:04:11+00:00

Have the following code: $(#blogs).mouseover( function () { $(this).addClass(hover); $(#home).removeClass(hover); $(#homepages).removeClass(hover); $(#apps).removeClass(hover); $(#facebook).removeClass(hover); $(#kontakt).removeClass(hover);

  • 0

Have the following code:

 $("#blogs").mouseover(
    function () {
      $(this).addClass("hover");

      $("#home").removeClass("hover");
      $("#homepages").removeClass("hover");
      $("#apps").removeClass("hover");
      $("#facebook").removeClass("hover");
      $("#kontakt").removeClass("hover");

      $("#content").hide().load("blogs.html", function(){
      $("#content").show("slide"); 

    });  
 });

Works all fine, but now I would like the load() / show() function only be called if #content does not already contain blogs.html.

In other words: I would like to check if blogs.html is already loaded and if yes, simply do nothing and only if not there yet I would load and show it.

Have tried some things with hasClass() and some if-formulas but struggle to get this check.

Tried stuff like this:

$("#content section").hasClass("check_blog").hide().load("blogs.html", function(){
$("#content").show("slide"); 

Basically I just need to know how I can check if blogs.html is already the contents of #content.

Thanks a lot for any help. Regards, Andi

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T07:04:13+00:00Added an answer on June 16, 2026 at 7:04 am

    Add an ID to some element in blogs.html, say blogsloaded, then you can check for it with:

    if (!$("#blogsloaded").length)
        $("#content").hide().load("blogs.html" ...
    

    Another method would be to store in a variable if you already loaded it:

    if (!this.blogsloaded)
    {
        this.blogsloaded=true;
        $("#content").hide().load("blogs.html" ...
    }
    
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