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Home/ Questions/Q 608649
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T17:28:59+00:00 2026-05-13T17:28:59+00:00

Have the following XML model <A></A> <B></B> <C></C> <D></D> Also have three classes class

  • 0

Have the following XML model

<A></A>
<B></B>
<C></C>
<D></D>

Also have three classes

class Foo1{
  public string A;
  public string B;
}
class Foo2{
  public string C;
  public string D;
}

class FooUnited{
  public Foo1 foo1;
  public Foo2 foo2;
}

The problem. I want to deserialize xml into object of FooUnited type. The brute-force idea is to manually select values from xml and initialize FooUnited object, but maybe there is a more elegant solution for that?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T17:29:00+00:00Added an answer on May 13, 2026 at 5:29 pm

    Assuming you have a root element you can use a DTO to wrap up the differences:

    public class MyDto {
        public string A {get;set;}
        public string B {get;set;}
        public string C {get;set;}
        public string D {get;set;}
    
        public FooUnited GetObject() {
            return new FooUnited {
                foo1 = new Foo1 { A = this.A, B = this.B },
                foo2 = new Foo2 { C = this.C, D = this.D },
            };
        }
    }
    
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