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Home/ Questions/Q 6163087
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T21:45:56+00:00 2026-05-23T21:45:56+00:00

Having a noob day. For some reason this works: // check for user in

  • 0

Having a noob day.

For some reason this works:

// check for user in db
$result = $connector->query('SELECT username FROM wallart_users 
                             WHERE username ="test@testmail.com");

if (mysql_num_rows($result) == 0) {
  ////// ADD NEW USER

But this doesn’t:

$payer_email = mysql_real_escape_string($payer_email);
// check for user in db
$result = $connector->query('SELECT username FROM wallart_users 
  WHERE username ='.$payer_email);

if (mysql_num_rows($result) == 0) {
  ////// NEW USER

The first one matches and sends me further down the page.
The second one doesn’t match (with or without the escape) and tries to create a new user with the same credentials (then fails as the user already exists).
The email address PayPal is sending is always the same, and the database contains the right address.
I have written both addresses to a log file during the process and they look identical.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T21:45:57+00:00Added an answer on May 23, 2026 at 9:45 pm
    'SELECT username FROM wallart_users WHERE username ="'.$payer_email.'"';
    
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