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Home/ Questions/Q 8270947
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T06:43:26+00:00 2026-06-08T06:43:26+00:00

Having issues mapping a ORACLE TIMESTAMP(9) field to java.sql.Timestamp or java.util.Date in Java Versions:-

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Having issues mapping a ORACLE TIMESTAMP(9) field to java.sql.Timestamp or java.util.Date in Java
Versions:-
ojdbc 11.2.0.1.0
hibernate-annotations 3.3.1.GA
ejb3-persistence 1.0.1.GA

Trying to map

UPDATE_TIMESTAMP_9 TIMESTAMP(9) NULL
TO
@Column(name = "UPDATE_TIMESTAMP_9")
private Date updateTimestamp_9;

Get Exception

org.hibernate.HibernateException: Wrong column type in EMPLOYEE.EMPLOYEE for column UPDATE_TIMESTAMP_9. Found: timestamp, expected: date

On investigating further i found that the code returns ‘false’ at the following line in Table.java

final boolean typesMatch = col.getSqlType( dialect, mapping ).toLowerCase()
                  .startsWith( columnInfo.getTypeName().toLowerCase() )
                  || columnInfo.getTypeCode() == col.getSqlTypeCode( mapping );
  1. col.getSqlType( dialect, mapping ) for Date or Timestamp field is date.
    columnInfo.getTypeName() is timestamp so the first part of the if query will not match

  2. col.getSqlTypeCode( mapping ) returns 93 (which is code for Types.TIMESTAMP). However, columnInfo.getTypeCode() returns 1111. So even the secondpart of the query doesnt match.

Problem is that while populating ColumnMetadata rs.getInt(“DATA_TYPE”) for field UPDATE_TIMESTAMP_9 returns a 1111 which is code for Types.OTHER. Please note that if i use TIMESTAMP(6) field in oracle columnInfo.getTypeCode() correctly returns 93 and the code successfully inserts a record. Problem is only with TIMESTAMP(9).

Cross posted here on hibernate forums

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T06:43:28+00:00Added an answer on June 8, 2026 at 6:43 am

    I disabled schema validation and it worked ok.

    Disable schema validation? – Steve Ebersole

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