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Home/ Questions/Q 8777799
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T19:21:53+00:00 2026-06-13T19:21:53+00:00

Having the following class: class Test { [MyAttr] public string Name; } How can

  • 0

Having the following class:

class Test {
  [MyAttr]
  public string Name;
}

How can I extend JSON.NET if I need to trim values of all properties marked with MyAttr to specific length? Seems I can’t do that in custom JsonConverter as I need access to MemberInfo representing the origin property.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T19:21:54+00:00Added an answer on June 13, 2026 at 7:21 pm

    After deeper reading the documentation and source code it looks like contract resolver is the way to go:

    public class MyCustomConverter : JsonConverter
    {
        public override bool CanConvert(Type objectType) {
            return true;
        }
    
        public override object ReadJson(Newtonsoft.Json.JsonReader reader, Type objectType, object existingValue, Newtonsoft.Json.JsonSerializer serializer) {
            throw new NotImplementedException();
        }
    
        public override void WriteJson(Newtonsoft.Json.JsonWriter writer, object value, Newtonsoft.Json.JsonSerializer serializer) {
            if (value == null) {
                writer.WriteNull();
                return;
            }
            string str = value.ToString().Substring(1, 2);
            writer.WriteValue(str);
        }
    }
    
    public class MaskContractResolver : DefaultContractResolver
    {
        protected override JsonProperty CreateProperty(MemberInfo member, MemberSerialization memberSerialization) {
            JsonProperty property = base.CreateProperty(member, memberSerialization);
            if (member.CustomAttributes.Any(x => typeof(MyAttr).IsAssignableFrom(x.AttributeType)))
                property.Converter = new MyCustomConverter();
            return property;
        }
    }
    

    As easy as pie!

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