Question

Having the following code:

function test(x) {
   if(x=='a') return false;
   return true;
}

if(y ==x) {
    return test('a');
    group['ids']= inputs.val();
    console.log(group);
}

why return true simply breaks my code by not continuing beyond the return?

Note: I want the return test()‘s answer to control if either it should continue with the code OR not

Update

I already do something like:

var response = test('b');
if (response==false) return false;
... more code here ...

But I want to avoid having to do so on every invoke of that function

Answer 1

Because that’s what return does in almost every programming language: it

1. exits the function and
2. returns a value

If you need other code to be executed, put it before the return statement.

Edit: I saw your edit, but it doesn’t change the very nature of return in that (and every) context. It will continue to stop the flow of the current scope, returning to the nearest higher scope with a value (in your case, true or false).