Question

Hello and thanks for being there,

I would like to pass a variable ($user) from a previous function to another one, but I need to use the arguments of the new function to pass the values that will render this new one.

Is there any way I can pass a variable from another function to a new function that only expects three arguments, and none of them is the variable from the previous function?

Example:

function my_function($country, $age, $colour) {
  if ($user = true) {
    echo "User is from " . $country . " and " . $age . " and his favourite colour is " . $colour; 
  }
}

my_function("italy", 19, "red");

It works if I put inside function my_function:

global $user;

but I believe using global variables is not a good practice.

Any idea on how to pass it as an argument? Should I just add it as another variable after $colour in the arguments of the new function?

Thanks a lot for your help 🙂

Answer 1

You can pass it as an argument, or better do this:

if ($user) my_function("italy", 19, "red");

since you don’t have to use the $user variable inside that function.