Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8920715
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T06:20:51+00:00 2026-06-15T06:20:51+00:00

Hello basically I tried to use this code for(int character=0; character<roomNo.length(); character++){ if((Character.isDigit(roomNo.charAt(character)))) {

  • 0

Hello basically I tried to use this code

    for(int character=0; character<roomNo.length(); character++){
        if((Character.isDigit(roomNo.charAt(character)))) {
        }
    }
    return true;

To loop through a String and see if it contains any numbers. I’m trying to create a method that checks whether a String is numeric, if it is the method should return true. So far it doesn’t work? Any help would be appreciated 🙂

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-15T06:20:52+00:00Added an answer on June 15, 2026 at 6:20 am

    Try this:

        for(int character=0; character<roomNo.length(); character++){
        if(!Character.isDigit(roomNo.charAt(character))) {
             return false;
        }
    }
    return true;
    

    Or as others have said, use regular expressions

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Hello not sure why Im getting this error. Basically I get it in these
Hello I have like this 2 tables class User public int UserId{get;set;} { ....
Hello every one this is basically extension to my previous question. i have write
Hello im coding a plugin for the game minecraft using Bukkit. Basically when a
Hello everyone and thank you very much for your time. Basically what I am
Hello people is it true that we cannot integrate Saxon with Visual Studio? Because
I've tried to simplify a problem I'm having with the code below. Some of
This question is related to: CS5 FLASH + AS3 Hello, I am simply trying
Consider the following bit of code: <UserControl x:Name=root> .... <TextBlock Text=Hello World Margin={Binding ElementName=root,
just wondering can anyone see anything wrong with this code. It worked perfectly on

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.