Hello for this program I am supposed to count the number of words in a string. So far, I have found out how to find the number of characters in a string but am unable to figure out how to turn the letters that make a word, and count it as 1 word.
My function is:
int wordcount( char word[MAX] ){
int i, num, counter, j;
num = strlen( word );
counter = 0;
for (i = 0; i < num; i++)
{
if (word[i] != ' ' || word[i] != '\t' || word[i] != '\v' || word[i] != '\f')
{
}
}
return counter;
}
I tried some variations, but the middle part of the if statement is where I am confused. How can I count the number of words in a string? Testing for this tests if the string has multiple spaces like “Hello this is a string”
Hints only since this is probably homework.
What you’re looking to count is the number of transitions between ‘word’ characters and whitespace. That will require remembering the last character and comparing it to the current one.
If one is whitespace and the other is not, you have a transition.
With more detail, initialise the
lastcharto whitespace, then loop over every character in your input. Where thelastcharwas whitespace and the current character is not, increase the word count.Don’t forget to copy the current character to
lastcharat the end of each loop iteration. And it should hopefully go without saying that the word count should be initialised to 0.