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Home/ Questions/Q 5961779
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Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T19:00:49+00:00 2026-05-22T19:00:49+00:00

hello i am stuck with jquery tablesorter: http://tablesorter.com/docs/index.html#Examples and would be grateful if some

  • 0

hello
i am stuck with jquery tablesorter:
http://tablesorter.com/docs/index.html#Examples

and would be grateful if some jquery guru could check my code to see where i am going wrong. instead of displaying 10 records per page it is displaying all records and also when i try to sort it does nothing. in addition to that, there are no zebra stripes appearing. all libraies are loaded and there are no errors in firebug. many thanks for your help.

<?php
$q=$_GET["q"];

$con = mysql_connect('localhost', 'root', '');
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("sample", $con);

$sql="SELECT * FROM logger_log WHERE idusr_log = '".$q."' order by datein_log desc";

$result = mysql_query($sql);

echo "<table id=\"userlog\" class=\"tablesorter\">
<thead>
<tr>
<th align=\"left\">Ip Address</th>
<th align=\"left\">Date In</th>
<th align=\"left\">Date Out</th>
</tr>
</thead>";

while($row = mysql_fetch_array($result))
  {
  echo "<tbody>";
  echo "<tr>";
  echo "<td>" . $row['ip_log'] . "</td>";
  echo "<td>" . date('d/m/Y H:i:s',strtotime($row['datein_log'])) . "</td>";
  echo "<td>" . date('d/m/Y H:i:s',strtotime($row['dateout_log'])) . "</td>";
  echo "</tr>";
  echo"</tbody>";
  }
echo "</table>";


mysql_close($con);
?>
<div id="pager" class="pager">
    <form>
        <img src="css/blue/first.png" class="first"/>
        <img src="css/blue/prev.png" class="prev"/>
        <input type="text" class="pagedisplay"/>
        <img src="css/blue/next.png" class="next"/>
        <img src="css/blue/last.png" class="last"/>
        <select class="pagesize">
            <option selected="selected"  value="10">10</option>
            <option value="20">20</option>
            <option value="30">30</option>
            <option  value="40">40</option>
        </select>
    </form>
</div>
<script type="text/javascript" src="js/jquery-1.3.2.min.js"></script>
<script type="text/javascript" src="js/jquery.tablesorter.min.js"></script>
<script type="text/javascript" src="js/jquery.tablesorter.pager.js"></script>
<link href="css/blue/style.css" rel="stylesheet" type="text/css" />
        <script>
        $(document).ready(function()     
        {   
            $("#userlog")
            .tablesorter({widthFixed: true, widgets: ['zebra']})     
            .tablesorterPager({container: $("#pager")});     

        } );
        </script>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T19:00:50+00:00Added an answer on May 22, 2026 at 7:00 pm

    You need to remove the <tbody> fom your results loop and place it around your while loop.

    echo "<tbody>";
      while($row = mysql_fetch_array($result)) {  
        echo "<tr>";
          echo "<td>" . $row['ip_log'] . "</td>";
          echo "<td>" . date('d/m/Y H:i:s',strtotime($row['datein_log'])) . "</td>";
          echo "<td>" . date('d/m/Y H:i:s',strtotime($row['dateout_log'])) . "</td>";
        echo "</tr>";  
      }
      echo"</tbody>";
    echo "</table>";
    
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