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Home/ Questions/Q 3795420
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T13:04:52+00:00 2026-05-19T13:04:52+00:00

Hello i am trying to create a grid in xmal that is populated via

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Hello i am trying to create a grid in xmal that is populated via a ViewModel.
The grid is a 5×5 grid, and my ViewModel contains a list of “MyObject”. This object contains 2 int variables Row and Column witch indicates where in the grid the Object should be.
MyObject is also a view models, and the grid space should be filled with Data Template names MyTemplate with the MyObject as the DataContext.
Now I pretty new to xaml and view models, but how would the best way of doing the be?

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  1. Editorial Team
    Editorial Team
    2026-05-19T13:04:53+00:00Added an answer on May 19, 2026 at 1:04 pm

    Let’s see…
    Put an ObservableCollection into the VM, then…

    Option 1:
    …a simple Grid into V. Subscribe to it’s CollectionChanged event from xaml.cs, add ContentControls for each Added object to grid, bind the ContentControl’s Grid.Row and Grid.Column property to each object’s properties, and set the DataContext to the object itself and ContentTemplate to Resources[“MyTemplate”]. (Also, for any removed objects find the corresponding ContentControl and remove it.)
    Pro: easy
    Con: .cs, no designer support

    Option 2:
    …an ItemsControl into V. Set its ItemPanelTemplate to a Grid, and bind your ObservableCollection to its ItemsSource. Then set your Itemtemplate to MyTemplate. Now, the trick is to make the items put in the correct cell, based on your values. For that, use the ItemsControl’s ItemContainerStyle property, and bind the container’s Grid.Row and Column to those properties.
    Pro: nice xaml and easily extended
    Con: ItemContainerStyle is tricky in WPF and missing in Silverlight, so in case of the latter, you can forget it

    Option 3:
    …a custom panel which you write. Inherit it from Grid perhaps. Than if an element is put into it, check if it’s DataContext implements an interface which contains your properties. Then use this as an ItemsPanel in Option 2…
    Pro: it should work perfectly
    Con: You have to write a new Panel for this…

    Hopefully one of these 3 will be ok for you.

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