Question

hello i am trying to get the output one time in while loop

While(1){
    if( current->tm_hour == 10 && current->tm_min == 0  ){
        Start_Function();
        std::cout <<  "Started" << std::endl;
    }

    if( current->tm_hour == 12 && current->tm_min == 0  ){
        End_Function();
        std::cout <<  "Ended" << std::endl;
    }

    Sleep(5000);
}

and i use sleep to refresh every 5 sec

so i want when the current Hour & minut = 10 & 00

it give me output Started and it call the function just one time and it contiune refreshing

Answer 1

Edit: In light of @Joachim Pileborg’s comment

It’s not the output that’s the problem, it’s that the functions are called (and the output printed) multiple times when it shouldn’t. – Joachim Pileborg

Alternate solution

int hasStarted = 0, hasEnded = 0;
While(1){
if( current->tm_hour == 10 && current->tm_min == 0 && !hasStarted  ){
Start_Function();
    std::cout <<  "Started" << std::endl;
    hasStarted = 1;
}

if( current->tm_hour == 12 && current->tm_min == 0  && !hasEnded ){
End_Function();
    std::cout <<  "Ended" << std::endl;
    hasEnded = 1;
}

Sleep(5000);
}
}

The code above will force it to only do each of the operation’s once and continue refreshing…

My original comment:

In the command line/terminal as you’ve foundout the output is printed out continuously. Depending on what operating system you use (window/linux/mac) the solution will be easy or not so easy.

I recommend looking up the gotoxy() function

http://www.programmingsimplified.com/c/conio.h/gotoxy

provided by the “conio.h” library for Windows or “ncurses.h” for Linux.

“ncurses.h” doesn’t have the gotoxy() but it will provide you with a way to do the same.