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Home/ Questions/Q 9321613
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Editorial Team
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Editorial Team
Asked: June 19, 20262026-06-19T03:53:15+00:00 2026-06-19T03:53:15+00:00

Hello i did a jquery ajax post that calls for a php form depending

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Hello i did a jquery ajax post that calls for a php form depending on the key : the key is get by the data-apphere is the code:

$(document).ready(function(){
    $('.form1').keyup(function(){
        var value = $(this).val();
        var key = $(this).data('app');
        $.post('page2.php', { key : value }, function(data){
            $("div[ data-show='" + key + "' ]").text(data); 
        });
    });
});

the problem is that where i specify the data value key instead of giving me the value data i want it names it as key, is there a way i can make the variable work? so that the key is equal to the data value, and not equal to key, because in the php it works if i do this $_POST['key']; but lets say data-app="username" then key will be equal to username and the php will read like this: $_POST['username']; hope is understandable and thanks 🙂

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  1. Editorial Team
    Editorial Team
    2026-06-19T03:53:16+00:00Added an answer on June 19, 2026 at 3:53 am

    Try:

    $(document).ready(function(){
        $('.form1').keyup(function(){
            var value = $(this).val();
            var key = $(this).data('app');
            var obj = {};
            obj[key] = value;
            $.post('page2.php', obj, function(data){
                $("div[ data-show='" + key + "' ]").text(data); 
            });
        });
    });
    
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