Question

Hello I have a chunk of memory (allocated with malloc()) that contains bits (bit literal), I’d like to read it as an array of char, or, better, I’d like to printout the ASCII value of 8 consecutively bits of the memory.

I have allocated he memory as char *, but I’ve not been able to take characters out in a better way than evaluating each bit, adding the value to a char and shifting left the value of the char, in a loop, but I was looking for a faster solution. Thank you

What I’ve wrote for now is this:

for allocation:

char * bits = (char*) malloc(1); 

for writing to mem:

ifstream cleartext; cleartext.open(sometext); while(cleartext.good()) {      c = cleartext.get();      for(int j = 0; j < 8; j++)      {  //set(index) and reset(index) set or reset the bit at bits[i]         (c & 0x80) ? (set(index)):(reset(index));//(*ptr++ = '1'):(*ptr++='0');          c = c << 1;      }.. }.. 

and until now I’ve not been able to get character back, I only get the bits printed out using:

printf('%s\n' bits); 

An example of what I’m trying to do is:

input.txt contains the string ‘AAAB’

My program would have to write ‘AAAB’ as ‘01000001010000010100000101000010’ to memory (it’s the ASCII values in bit of AAAB that are 65656566 in bits)

Then I would like that it have a function to rewrite the content of the memory to a file.

So if memory contains again ‘01000001010000010100000101000010’ it would write to the output file ‘AAAB’.

Answer 1

int numBytes = 512; char *pChar = (char *)malloc(numBytes); for( int i = 0; i < numBytes; i++ ){    pChar[i] = '8'; } 

Since this is C++, you can also use ‘new’:

int numBytes = 512; char *pChar = new char[numBytes]; for( int i = 0; i < numBytes; i++ ){    pChar[i] = '8'; }