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Home/ Questions/Q 553229
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:34:59+00:00 2026-05-13T11:34:59+00:00

Hello I have an unsigned char * that looks (after printf) like this (it’s

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Hello I have an unsigned char * that looks (after printf) like this (it’s a SHA-1 hash):

n\374\363\327=\3103\231\361P'o]Db\251\360\316\203

I need to convert this unsigned char * to an unsigned int, what do you think it would be the best way to do it ? I have some ideas, but I’m not a C expert so wanted to see someone else ideas before trying my own stuff.

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:34:59+00:00Added an answer on May 13, 2026 at 11:34 am

    Why would you need a conversion? It’s a 160 bit long digest. Digests are used only in two ways:

    You print a digest with something like

    for (i = 0; i < 20; ++i) {
        printf("%2x", digest[i]);
    }
    

    and compare against another digest with something like

    for (i = 0, equals = 1; i < 20; ++i) {
        if (a[i] != b[i]) {
            equals = 0;
        }
    }
    

    It works just fine the way it is as a 20-byte long array of bytes. You don’t have to worry about endianness, word length, nothing.

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