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Home/ Questions/Q 6834881
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:09:56+00:00 2026-05-26T23:09:56+00:00

Hello i have some question about java. here is my code: public static void

  • 0

Hello i have some question about java.
here is my code:

public static void main(String[] args) throws Exception {
    Process pr = Runtime.getRuntime().exec("java -version");

    BufferedReader in = new BufferedReader(new InputStreamReader(pr.getInputStream()));
    String line;
    while ((line = in.readLine()) != null) {
        System.out.println(line);
    }
    pr.waitFor();
    System.out.println("ok!");

    in.close();
    System.exit(0);
}

in that code i’am trying to get a java version command execute is ok, but i can’t read the output it just return null. Why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:09:57+00:00Added an answer on May 26, 2026 at 11:09 pm

    Use getErrorStream().

    BufferedReader in = new BufferedReader(new InputStreamReader(pr.getErrorStream()));
    

    EDIT:

    You can use ProcessBuilder (and also read the documentation)

    ProcessBuilder   ps=new ProcessBuilder("java.exe","-version");
    
    //From the DOC:  Initially, this property is false, meaning that the 
    //standard output and error output of a subprocess are sent to two 
    //separate streams
    ps.redirectErrorStream(true);
    
    Process pr = ps.start();  
    
    BufferedReader in = new BufferedReader(new InputStreamReader(pr.getInputStream()));
    String line;
    while ((line = in.readLine()) != null) {
        System.out.println(line);
    }
    pr.waitFor();
    System.out.println("ok!");
    
    in.close();
    System.exit(0);
    
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