Question

Hello I wish not to disturb but I’m newer to developing program.

I’m trying to make a video playing in an activity but I get always black screen.

My video is in mp4 h264 created with ffmpeg with android profile and plays in quicktime and is set in res/raw/corsolex_1.mp4

I attach the code I’m writing to understand what I miss to do, if someone can help I’m very grateful.

Angelo

this activity is called Clipvideo1

package com.wocmultimedia.VideoEditLesson1;

import android.app.Activity;
import android.media.MediaPlayer;
import android.os.Bundle;

public class Clipvideo1 extends Activity {@Override
     protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.clip1);

// Put the media file into the res/raw folder of your application
MediaPlayer mp = MediaPlayer.create(this, R.raw.corsolex_1);
mp.start();
}}

this is the XML layout called clip1.xml

<FrameLayout android:id="@+id/linearLayout1" 
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent" 
    xmlns:android="http://schemas.android.com/apk/res/android">
        <VideoView android:id="@+id/videoView1" 
        android:layout_width="wrap_content" 
        android:layout_height="wrap_content"></VideoView>

    </FrameLayout>

Answer 1

You don’t link the video to VideoView somehow.

So as you see you have 3 parts of the uri:

1. “android.resource://”
2. “com.wocmultimedia.VideoEditLesson1”
3. your resource

“corsolex_1” is the name of your video

Maybe this code helps:

@Override
    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.clip1);

    VideoView videoView = (VideoView) findViewById(R.id.videoView1);

    Uri videoPath = Uri.parse("android.resource://" + getPackageName() + "/" + R.raw.corsolex_1);

    videoView.setVideoURI(videoPath);
    videoView.requestFocus();
    videoView.start();

    }