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Home/ Questions/Q 7659555
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T13:20:54+00:00 2026-05-31T13:20:54+00:00

Hello I’m building spring-hibernate application. Do i realy need configuration from below ? <property

  • 0

Hello I’m building spring-hibernate application. Do i realy need configuration from below ?

    <property name="annotatedClasses">
        <list>
            <value>org.fixus.springer.model.User</value>
        </list>
    </property>

I’ve set annotation-driven in my root-context.xml

<mvc:annotation-driven />
<context:component-scan base-package="org.fixus.springer" />
<context:component-scan base-package="org.fixus.springer.model" />

Now shouldn’t hibernate automaticly take everything from this packages with annotation @Entity and convert it to table ? As for now without annotatedClasses he won’t create a table from a entity

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T13:20:54+00:00Added an answer on May 31, 2026 at 1:20 pm

    Use the docs, Luke!

    […]Example for an AnnotationSessionFactoryBean bean definition:

    <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
        <property name="dataSource" ref="dataSource"/>
        <property name="annotatedClasses">
            <list>
                <value>test.package.Foo</value>
                <value>test.package.Bar</value>
            </list>
        </property>
    </bean>
    

    Or when using classpath scanning for autodetection of entity classes:

    <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
        <property name="dataSource" ref="dataSource"/>
        <property name="packagesToScan" value="test.package"/>
    </bean>
    

    As you can see you have a choice between defining all classes explicitly or only the package for scanning. <context:component-scan/> does not recognize Hibernate/JPA annotations and hence has no effect.

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