Question

hello i’m building website in which i need the functionality of retriving video ( if video), images, descirption from different links, like different video websites or if general website link get thumbnail and descirption.

is there any php class exist ? for this taks Please help me suggest better solution Thanks in advance…

oh yeah example is just like facebook link tab

Answer 1

Firstly you more than likely referring to video sites such as Youtube and Vimeo.

Both sites have an API Features that you can use to get your video information:

• Vimeo
  • http://vimeo.com/api
• Youtube
  • http://www.youtube.com/dev
  • http://code.google.com/apis/youtube/overview.html
  • http://code.google.com/apis/youtube/2.0/developers_guide_php.html

For a extensive frameowrk in youtube api requests you can use Zend Data: http://framework.zend.com/download/gdata

for a Vimeo PHP Library use https://github.com/vimeo/vimeo-php-lib

Most other professional sites will have some sort of API out there, and there would more than likely be libraries for them.

---

Is there any native classes that interact with all these websites ?

Short answer is no, All there API’s are different, therefore no single class can interact with all the websites successfully.

What you need to do is create a Driver based package to handle this.

You base class would look something like so:

class VideoAPI
{
    private $driver;
    public function __construct($driver)
    {
        require_once "drivers/" . $driver . ".class.php";
        $driverClass = $driver . "_Driver";

        $this->driver = new $driverClass;
    }

    public function FetchVideoById($id)
    {
        return $this->driver->FetchVideoById($id);
    }
}

You would then have an interface for your drivers like so:

interface IVideoDriver
{
    public function FetchVideoById($id);
    /*.
        Other required methods
    .*/
}

and each driver would implement the method and extend the request class like so:

class Youtube_Driver extends VideoRequest implements IVideoDriver
{
    protected $base_url = "http://gdata.youtube.com"
    public function FetchVideoById($id)
    {
        $Request = $this->request($this->base_url . "/feeds/api/videos/",array(
            "format" => "json",
            "api_id" => $this->config->api_keys->youtube
        ));

        if($Request->status() == VideoRequest::STATUS_OK)
        {
             return $Request->Response();
        }
    }
}