Question

hello i’m going to get array data from for. i have a code but it works not good
in the previous code cs=2

for($k=0;$k<$cs;$k++)
{ 


$SQL = "SELECT duration FROM core_network WHERE location=('".$location_c[$k]."')";
$result = mysql_query($SQL);


$cks="0";
$duration=array();
while ($db_field = mysql_fetch_array($result)) {
$duration_c[$cks]= $db_field['duration']; //*here must save to data
 $cks++;

} 
 }

i have saved this code in the search_l.php

 <?php include("lib/search_l.php"); ?>



  <?php
if($cs!=0){
for($i=0;$i<$cs;$i++)
{ 

?>



 <div id="alarmdisplay">
   <table class width="634" border="0" cellspacing="3" cellpadding="3">
  <tr class="search">
    <td width="256"><?php echo $location_c[$i] ?></td>
    <td width="154" class="247"><?php  echo $duration_c[$i]
?></td>
    <td width="194">&nbsp;</td>
  </tr>
 </table>

in here it must be print 2 duration. but it prints only one others have error Notice: Undefined offset: 1 in how to print it by correct?

when i test it to check correct i noticed that:

$result)) {
$duration_c[$cks]= $db_field['duration'];
 $cks++;

} echo $duration_c[$cks]   //*it prints correct i meant prints 2 test data
}

after that

$result)) {
$duration_c[$cks]= $db_field['duration'];
 $cks++;

}  
}
echo $duration_c[$cks]  //*it prints not correct i meant prints only first test data

how to correct it?

Answer 1

$duration_c=array();//Should be declared outside loop

for($k=0;$k<$cs;$k++)
 { 
  $SQL = "SELECT duration FROM core_network WHERE location=('".$location_c[$k]."')";
  $result = mysql_query($SQL);
  $cks = 0;//String variable
  while ($db_field = mysql_fetch_array($result,MYSQL_ASSOC)) {
                                                    //^---------returns associative array
      $duration_c[$cks]= $db_field['duration'];
      $cks++;
   } 
 }