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Home/ Questions/Q 7418543
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T07:54:24+00:00 2026-05-29T07:54:24+00:00

Hello this is my code String url = http://en.wikipedia.org/w/index.php?title=Special%%3ASearch&search=+q.getAuthor().replace( ,%20)+; Uri uri = Uri.parse(url);

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Hello this is my code

String url = "http://en.wikipedia.org/w/index.php?title=Special%%3ASearch&search="+q.getAuthor().replace(" ","%20")+"";
                Uri uri = Uri.parse(url);
                Intent intent = new Intent(Intent.ACTION_VIEW, uri);

but it is not showing the result instead it shows web page you requested is temporarily down

is there anything wrong with the code or what

thanks in advance…

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  1. Editorial Team
    Editorial Team
    2026-05-29T07:54:25+00:00Added an answer on May 29, 2026 at 7:54 am

    He shouldn’t need the Internet permission since this is just launching an intent that the browser is going to pick up.

    my guess is either that your device is offline (no 3g/4g, and no wifi) or your url is not working correctly.

    make a log statement that prints your url before you parse it to a uri. Then copy the url out of your log and paste it into a browser and see if it loads.

    You might consider not doing the urlencoding manually with String.replace();

    Java provides you with URLEncoder which has static methods that will handle the encoding for you.

    Just encode all of your parameter and then append them to your base url.

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