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Home/ Questions/Q 9020833
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T05:06:55+00:00 2026-06-16T05:06:55+00:00

Help will be most appreciated. This is the code from the Jquery website <button

  • 0

Help will be most appreciated.

This is the code from the Jquery website

    <button id="refresh">refresh</button>
    <div id="images"></div>

    $("#refresh").click(function(){ 
        $.getJSON("http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?",
                {
                    tags: "vw beetle",
                    tagmode: "any",
                    format: "json"
                },    

                function(data) {   
                    $.each(data.items, function(i, item) {
                        $("<img/>").attr("src", item.media.m).empty().appendTo("#images");
                        if (i == 3)
                    return false;

                    });
                });
      });

This is racking my brain, I want to replace the results, not keep adding or appending to the results when the refresh button is clicked.

Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T05:06:57+00:00Added an answer on June 16, 2026 at 5:06 am

    I think you want to empty #images:

    function (data) {
       $("#images").empty();
       $.each(data.items...
    
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