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Home/ Questions/Q 814063
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T01:27:41+00:00 2026-05-15T01:27:41+00:00

Help with unit testing checkbox behavior. I have this page: <!DOCTYPE html> <html> <head>

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Help with unit testing checkbox behavior. I have this page:

<!DOCTYPE html>
<html>
<head>
    <title></title>
    <script type="text/javascript" src="../js/jquery-1.4.2.min.js"></script>
    <script type="text/javascript">
        $(function() {
            $('<div><input type="checkbox" name="makeHidden" id="makeHidden" checked="checked" />Make Hidden</div>').appendTo('body');
            $('<div id="displayer" style="display:none;">Was Hidden</div>').appendTo('body');

            $('#makeHidden').click(function() {
                var isChecked = $(this).is(':checked');

                if (isChecked) {
                    $('#displayer').hide();
                }
                else {
                    $('#displayer').show();
                }
                return false;
            });

        });

    </script>
</head>
<body>
</body>
</html>

This doesn’t work it is because of the return false; in the click handler. If I remove it it works great. The problem is if I pull the click function out into it’s own function and unit test it with qunit it will not work without the return false;

[EDIT]
Using @patrick’s answer my results are:

Firefox:

  • Manual test of toy – good.
  • Unit Tests – good.
  • Manual test of production app – good.

Internet Explorer:

  • Manual test of toy – fail.
  • Unit Tests – good.
  • Manual test of production app – fail.

Internet Explorer requires initially, one-click. after that it requires two clicks.

I thought jQuery is to abstract away browsers?

Am I going to have to override the entire check box behavior for a solution?

In my unit tests this is how I am doing the check box simulation of a user:

$(':input[name=shipToNotActive]').removeAttr('checked');
$('#shipToNotActive').change();

and also:

$(':input[name=shipToNotActive]').attr('checked', 'checked');
$('#shipToNotActive').change();
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T01:27:41+00:00Added an answer on May 15, 2026 at 1:27 am

    How about using change instead of click?

    $('#makeHidden').change(function() {
                var isChecked = $(this).is(':checked');
    
                if (isChecked) {
                    $('#displayer').hide();
                }
                else {
                    $('#displayer').show();
                }
                return false;
            });
    

    The return false; won’t be in the way since the event is fired as a result of the change having occurred.

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