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Home/ Questions/Q 879333
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T11:54:53+00:00 2026-05-15T11:54:53+00:00

Here are four simple invocations of assert: >>> assert 1==2 Traceback (most recent call

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Here are four simple invocations of assert:

>>> assert 1==2
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
AssertionError

>>> assert 1==2, "hi"
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
AssertionError: hi

>>> assert(1==2)
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
AssertionError

>>> assert(1==2, "hi")

Note that the last one does not raise an error. What is the difference between calling assert with or without parenthesis that causes this behavior? My practice is to use parenthesis, but the above suggests that I should not.

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  1. Editorial Team
    Editorial Team
    2026-05-15T11:54:54+00:00Added an answer on May 15, 2026 at 11:54 am

    The last assert would have given you a warning (SyntaxWarning: assertion is always true, perhaps remove parentheses?) if you ran it through a full interpreter, not through IDLE. Because assert is a keyword and not a function, you are actually passing in a tuple as the first argument and leaving off the second argument.

    Recall that non-empty tuples evaluate to True, and since the assertion message is optional, you’ve essentially called assert True when you wrote assert(1==2, "hi").

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