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Home/ Questions/Q 7517869
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T01:35:27+00:00 2026-05-30T01:35:27+00:00

Here I have a code: cout << Press Enter To Exit…; cin.ignore(); this program

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Here I have a code:

cout << "Press Enter To Exit...";
cin.ignore();

this program will execute and will wait till you press enter and then it will exit.
now see this code:

int m;
cin >> m;
cout << "Press Enter To Exit...";
cin.ignore();

this time after entering a number for saving in “m” the program will exit without waiting for cin.ignore command which waits for pressing enter.

I mean if you use cin command before cin.ignore, the cin.ignore command will skip. why? and what should I do for fixing it?

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  1. Editorial Team
    Editorial Team
    2026-05-30T01:35:28+00:00Added an answer on May 30, 2026 at 1:35 am

    Use this.

    std::cin.sync(); std::cin.get();
    
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