Question

Here I have pasted my code, I want to return the response of $.ajax as response of function a(). But before the result comes up of ajax call, it is returning the empty f. please help on this

a = function()
{
        var f = '';
    $.ajax({
          url: 'http://api.twitter.com/1/statuses/user_timeline.json?screen_name=immaulikvora&count=1&page=1&include_entities=1&callback=?',
          dataType: 'json',
          async: false,
          success: function(data) {
            f = data;
          }
        });    
    return f;
};


var lid = a();

alert(lid);

Answer 1

I guess you are using jQuery 1.8+

http://api.jquery.com/jQuery.ajax/

Please read the fine print.

As of jQuery 1.8, the use of async: false with jqXHR ($.Deferred) is
deprecated;

you must use the complete/success/error callbacks.

try

http://jsfiddle.net/UgrLE/