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Home/ Questions/Q 6888023
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T05:57:27+00:00 2026-05-27T05:57:27+00:00

Here I have string like this 1322485986.672901000 , data type is string which represents

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Here I have string like this "1322485986.672901000", data type is string which represents unixtime. I want to convert it into datetime in Python.

The way I used is date = datetime.fromtimestamp(float(row[0])) row[0] represents value like this 1322485986.672901000, since I have several rows. The convert result is wrong, it only calculates the digits before the dot. So the date after conversion is like 2011-11-28 13:53:23.6729

I think the problem is float(row[0]), but I don’t know how to solve this problem, or does anyone know how to convert unixtime to datetime in a better way?

Many thanks!

Now the result I got is 2011-11-28 14:13:06.672901

But when using an online converter, the result is 2011-11-28 13:13:06

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  1. Editorial Team
    Editorial Team
    2026-05-27T05:57:28+00:00Added an answer on May 27, 2026 at 5:57 am

    Your one-hour difference in the current result is likely the consequence of time zone application.

    You can supply an explicit time zone if you need to — the docs on tzinfo objects can steer you straight on creating your time zone object, and once it’s created, you just pass in the argument:

    from datetime import datetime, tzinfo, timedelta
    
    timestamp = "1322485986.672901000"
    
    class UTC(tzinfo):
        def utcoffset(self, dt):
             return timedelta(0)
        def tzname(self, dt):
            return "UTC"
        def dst(self, dt):
            return timedelta(0)
    
    
    d1 = datetime.fromtimestamp(float(timestamp), UTC())
    print d1
    

    This code prints 2011-11-28 13:13:06.672901+00:00 for me.

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