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Home/ Questions/Q 6833499
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:59:10+00:00 2026-05-26T22:59:10+00:00

Here is a case where a thread is waiting for notify() or a timeout.

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Here is a case where a thread is waiting for notify() or a timeout. Here a while loop is added to handle spurious wake up.

boolean dosleep = true;
while (dosleep){
    try {
        wait(2000);
        /**
         * Write some code here so that
         * if it is spurious wakeup, go back and sleep.
         * or if it is timeout, get out of the loop. 
         */

    } catch (InterruptedException e) {
        e.printStackTrace();
    }
}

In this case how can I distinguish between a spurious wake up and time out? If it is a spurious wake up, i need to go back and wait. And if it is a timeout, i need to get out of the loop.

I can easily identify the case of notify(), because i will be setting the dosleep variable to false while notify() call.

EDIT: i am using 1.4 java version, due to embedded project requirement. I cannot use Condition as it is available only post 1.5.

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-26T22:59:10+00:00Added an answer on May 26, 2026 at 10:59 pm

    You need to keep track of your timeout if you want to distinguish the two cases.

    long timeout = 2000;
    long timeoutExpires = System.currentTimeMillis() + timeout;
    while(dosleep) {
      wait(timeout);
      if(System.currentTimeMillis() >= timeoutExpires) {
        // Get out of loop
        break;
      }
    }
    

    That said, denis’s recommendation of using the Condition class is the better way to do this.

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