Here is a code i am having problem with —
public class WaitTest {
public static void main(String[] args) {
Runner rr = new Runner();
Thread t1 = new Thread(rr,"T1");
Thread t2 = new Thread(rr,"T2");
t1.start();
t2.start();
}
}
class Runner implements Runnable{
int i=0;
public void run(){
try{
if(Thread.currentThread().getName().equals("T1")){
bMethod();
aMethod();
}
else{
aMethod();
bMethod();
}
}catch(Exception e){}
}
public synchronized void aMethod() throws Exception{
System.out.println("i="+i+",Now going to Wait in aMethod "+Thread.currentThread().getName());
Thread.currentThread().wait();
System.out.println("Exiting aMethod "+Thread.currentThread().getName());
}
public synchronized void bMethod() throws Exception{
System.out.println("i="+i+",Now going to Wait bMethod "+Thread.currentThread().getName());
i=5;
notifyAll();
System.out.println("Exiting bMethod "+Thread.currentThread().getName());
}
}
The output is :
i=0,Now going to Wait bMethod T1
Exiting bMethod T1
i=5,Now going to Wait in aMethod T1
i=5,Now going to Wait in aMethod T2
My question is :
Why T2 enters in
aMethodwhileT1is waiting inside? and WhyT2prints
i=5inaMethod.
When you execute
wait, your thread releases the lock and enters the wait state. At this time the other thread is allowed to enter the method. You are using a single instance ofRunnableso when one thread sets it to 5, that’s what the other thread reads.