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Home/ Questions/Q 9221875
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T03:40:38+00:00 2026-06-18T03:40:38+00:00

Here is a code of a class of Linked List , i have a

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Here is a code of a class of Linked List , i have a question on the function Singly_linked_list *GetNext().What does that means if a class name is stated before the function name? Is that a data type?Also,same question on the data member Singly_linked_list *nextPtr.I Please help
Thank you

class Singly_linked_list // Use a class Singly_linked_list to represent an object{
public:
// constructor initialize the nextPtr
Singly_linked_list()
{
    nextPtr = 0; // point to null at the beginning
}

// get a number
int GetNum()
{
    return number;
}

// set a number
void SetNum(int num)
{
    number = num;
}

// get the next pointer
Singly_linked_list *GetNext()
{
    return nextPtr;
}

// set the next pointer
void SetNext(Singly_linked_list *ptr)
{
    nextPtr = ptr;
}

 private:
int number;
Singly_linked_list  *nextPtr;
 };
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  1. Editorial Team
    Editorial Team
    2026-06-18T03:40:39+00:00Added an answer on June 18, 2026 at 3:40 am
    // get the next pointer
    Singly_linked_list *GetNext()
    {
        return nextPtr;
    }
    

    This means the function GetNext returns a pointer to an instance of the class Singly_linked_list.

    Likewise

    Singly_linked_list  *nextPtr;
    

    means nextPtr is a pointer to an instance of the class Singly_linked_list.

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