Question

Here is a function similar to the one I’ve defined:

void Function( BYTE *data );

What I would like to do is something like this:

Function( new BYTE { 0x00, 0x00 } );

Answer 1

You cannot use the array initialiser syntax with dynamically allocated arrays using new. You could do something like this:

BYTE *ary=new BYTE[2];
ary[0] = 0;
ary[1] = 0;
Function(ary);
delete [] ary;

But why are you using dynamically allocated memory here? Is the array held onto outside of the scope of the current function? If not, you can use an array allocated on the stack:

BYTE ary[2] = {0};
Function(ary);

In C++, a preferred method is to use the STL class std::vector which acts like a dynamically allocated (but type safe) array:

std::vector<BYTE> ary(2);
Function(&ary[0]);