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Home/ Questions/Q 8694099
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T00:42:17+00:00 2026-06-13T00:42:17+00:00

Here is a piece of python code (result is a nested list created before)

  • 0

Here is a piece of python code (“result” is a nested list created before)

for i in range(len(result)-1):
    try:
        result[i][3]=0
        result[i+i][0]=0
    except IndexError:
        print "fail", result[i][3], result[i+1][0], i, len(result)
return result

which, to my astonishment, quite often prints “fail” (with non-revealing values for i, len(result), e.g. 24, 31). How can

result[i][3]=0
result[i+i][0]=0

produce the IndexError exception, if

print result[i][3], result[i+1][0]

does not?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T00:42:18+00:00Added an answer on June 13, 2026 at 12:42 am

    You are accessing the index i + i, not i + 1:

    result[i+i][0]=0
    

    This means that by the time you reach i // 2 + 1 you have an index error, whatever the size of your list.

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