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Home/ Questions/Q 6690819
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T05:40:50+00:00 2026-05-26T05:40:50+00:00

Here is a set of structured 3D points . Now we can form a

  • 0

Here is a set of structured 3D points. Now we can form a BSpline using these points as knots.

dat=Import["3DFoil.mat", "Data"]
fu=BSplineFunction[dat]

Here we can do a ParametricPlot3D with these points.

pic=ParametricPlot3D[fu[u,v],{u, 0, 1}, {v, 0, 1}, Mesh -> All, AspectRatio -> 
Automatic,PlotPoints->10,Boxed-> False,Axes-> False]

enter image description here

Question

If we carefully look at the 3D geometry coming out of the spline we can see that it is a hollow structure. This hole appears in both side of the symmetric profile. How can we perfectly (not visually!) fill up this hole and create a unified Graphics3D object where holes in both sides are patched.

enter image description here

What I am able to get so far is the following. Holes are not fully patched.
enter image description here

I am asking too many questions recently and I am sorry for that. But if any of you get interested I hope you will help.

Update

Here is the problem with belisarius method.
It generates triangles with almost negligible areas.

dat = Import[NotebookDirectory[] <> "/3DFoil.mat", "Data"];
(*With your points in "dat"*)
fd = First@Dimensions@dat;
check = ParametricPlot3D[{BSplineFunction[dat][u, v], 
BSplineFunction[{dat[[1]], Reverse@dat[[1]]}][u, v], 
BSplineFunction[{dat[[fd]], Reverse@dat[[fd]]}][u, v]}, {u, 0, 
1}, {v, 0, 1}, Mesh -> All, AspectRatio -> Automatic, 
PlotPoints -> 10, Boxed -> False, Axes -> False]

output is here
enter image description here

Export[NotebookDirectory[]<>"myres.obj",check];
cd=Import[NotebookDirectory[]<>"myres.obj"];
middle=
check[[1]][[2]][[1]][[1(* Here are the numbers of different Graphics group*)]][[2,1,1,1]];
sidePatch1=check[[1]][[2]][[1]][[2]][[2,1,1,1]];
sidePatch2=check[[1]][[2]][[1]][[3]][[2,1,1,1]];

There are three Graphics groups rest are empty. Now lets see the area of the triangles in those groups.

polygonArea[pts_List?
(Length[#]==3&)]:=Norm[Cross[pts[[2]]-pts[[1]],pts[[3]]-pts[[1]]]]/2
TriangleMaker[{a_,b_,c_}]:={vertices[[a]],vertices[[b]],vertices[[c]]}
tring=Map[polygonArea[TriangleMaker[#]]&,middle];
tring//Min

For the middle large group output is

0.000228007

This is therefore a permissible triangulation. But for the side patches we get zero areas.

Map[polygonArea[TriangleMaker[#]] &, sidePatch1] // Min
Map[polygonArea[TriangleMaker[#]] &, sidePatch2] // Min

Any way out here belisarius ?

My partial solution

First download the package for simplifying complex polygon from Wolfram archive.

fu = BSplineFunction[dat];
pic =(*ParametricPlot3D[fu[u,v],{u,0,1},{v,0,1},Mesh->None,
AspectRatio->Automatic,PlotPoints->25,Boxed->False,Axes->False,
BoundaryStyle->Red]*)
ParametricPlot3D[fu[u, v], {u, 0, 1}, {v, 0, 1}, Mesh -> None, 
AspectRatio -> Automatic, PlotPoints -> 10, Boxed -> False, 
Axes -> False, BoundaryStyle -> Black];
bound = First@Cases[Normal[pic], Line[pts_] :> pts, Infinity];
corners = Flatten[Table[fu[u, v], {u, 0, 1}, {v, 0, 1}], 1];
nf = Nearest[bound -> Automatic]; {a1, a2} = 
Union@Flatten@(nf /@ corners);
sets = {bound[[2 ;; a1]], bound[[a1 ;; a2]],bound[[a2 ;; a2 + a1]]};
CorrectOneNodeNumber = Polygon[sets[[{1, 3}]]][[1]][[1]] // Length;
CorrectOneNodes1 = 
Polygon[sets[[{1, 3}]]][[1]][[1]]; CorrectOneNodes2 = 
Take[Polygon[sets[[{1, 3}]]][[1]][[2]], CorrectOneNodeNumber];
<< PolygonTriangulation`SimplePolygonTriangulation`
ver1 = CorrectOneNodes1;
ver2 = CorrectOneNodes2;
triang1 = SimplePolygonTriangulation3D[ver1];
triang2 = SimplePolygonTriangulation3D[ver2];
Show[Graphics3D[{PointSize[Large], Point[CorrectOneNodes1]},Boxed -> False,
BoxRatios -> 1], Graphics3D[{PointSize[Large], Point[CorrectOneNodes2]},
Boxed -> False, BoxRatios -> 1],
Graphics3D[GraphicsComplex[ver1, Polygon[triang1]], Boxed -> False,
BoxRatios -> 1],
Graphics3D[GraphicsComplex[ver2, Polygon[triang2]], Boxed -> False,
BoxRatios -> 1]]

We get nice triangles here.

picfin=ParametricPlot3D[fu[u,v],{u,0,1},  {v,0,1},Mesh->All,AspectRatio->Automatic,PlotPoints->10,Boxed->False,Axes->False,BoundaryStyle->None];pic3D=Show[Graphics3D[GraphicsComplex[ver1,Polygon[triang1]]],picfin,Graphics3D[GraphicsComplex[ver2,Polygon[triang2]]],Boxed->False,Axes->False]

enter image description here
enter image description here

Now this has just one problem. Here irrespective of the PlotPoints there are four triangles always appearing that just shares only one edge with any other neighboring triangle. But we expect all of the triangles to share at least two edges with other trangles. That happens if we use belisarius method. But it creates too small triangles that my panel solver rejects as tingles with zero area.

One can check here the problem of my method. Here we will use the method from the solution by Sjoerd.

Export[NotebookDirectory[]<>"myres.obj",pic3D];
cd=Import[NotebookDirectory[]<>"myres.obj"];
polygons=(cd[[1]][[2]]/.GraphicsComplex-> List)[[2]][[1]][[1,1]];
pt=(cd[[1]][[2]]/.GraphicsComplex-> List)[[1]];
vertices=pt;
(*Split every triangle in 3 edges,with nodes in each edge sorted*)
triangleEdges=(Sort/@Subsets[#,{2}])&/@polygons;
(*Generate a list of edges*)
singleEdges=Union[Flatten[triangleEdges,1]];
(*Define a function which,given an edge (node number list),returns the bordering*)
(*triangle numbers.It's done by working through each of the triangles' edges*)
ClearAll[edgesNeighbors]
edgesNeighbors[_]={};
MapIndexed[(edgesNeighbors[#1[[1]]]=Flatten[{edgesNeighbors[#1[[1]]],#2[[1]]}];
edgesNeighbors[#1[[2]]]=Flatten[{edgesNeighbors[#1[[2]]],#2[[1]]}];
edgesNeighbors[#1[[3]]]=Flatten[{edgesNeighbors[#1[[3]]],#2[[1]]}];)&,triangleEdges];

(*Build a triangle relation table.Each'1' indicates a triangle relation*)
relations=ConstantArray[0,{triangleEdges//Length,triangleEdges//Length}];
Scan[(n=edgesNeighbors[##];
If[Length[n]==2,{n1,n2}=n;
relations[[n1,n2]]=1;relations[[n2,n1]]=1];)&,singleEdges]
(*Build a neighborhood list*)
triangleNeigbours=Table[Flatten[Position[relations[[i]],1]],{i,triangleEdges//Length}];
trires=Table[Flatten[{polygons[[i]],triangleNeigbours[[i]]}],{i,1,Length@polygons}];
Cases[Cases[trires,x_:>Length[x]],4]

Output shows always there are four triangles that shares only one edges with others.

{4,4,4,4}

In case of belisarius method we don’t see this happening but there we get triangles with numerically zero areas.

BR

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:40:51+00:00Added an answer on May 26, 2026 at 5:40 am

    Your data set looks like this:

    Graphics3D[Point@Flatten[dat, 1]]
    

    enter image description here

    It consists of 22 sections of 50 points.

    Adding a mid-line in each end section (which is actually the end section flattened):

    dat2 = Append[Prepend[dat, 
                          Table[(dat[[1, i]] + dat[[1, -i]])/2, {i, Length[dat[[1]]]}]
                  ], 
                  Table[(dat[[-1, i]] + dat[[-1, -i]])/2, {i, Length[dat[[-1]]]}]
           ];
    
    Graphics3D[{Point@Flatten[dat, 1], Red, Point@dat2[[1]], Green, Point@dat2[[-1]]}]
    

    enter image description here

    Now add some weights to the wingtip rim:

    sw = Table[1, {24}, {50}];
    sw[[2]] = 1000 sw[[1]];
    sw[[-2]] = 1000 sw[[1]];
    fu = BSplineFunction[dat2, SplineWeights -> sw];
    
    Show[
      ParametricPlot3D[fu[u, v], {u, 0, 1}, {v, 0, 1}, Mesh -> All, 
                          AspectRatio -> Automatic, PlotPoints -> 20, Boxed -> False, 
                          Axes -> False, Lighting -> "Neutral"
      ], 
      Graphics3D[{PointSize -> 0.025, Green, Point@dat2[[-1]], Red,Point@dat2[[-2]]}]
    ]
    

    enter image description here

    Note that I increased the PlotPoints value to 20.

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