Question

Here is a snippet:

for arg in "$@"; do
    if [ $arg == "--coverage" ]; then
        ENABLE_COVERAGE=1
        shift
    elif [ $arg == "--mysql" ]; then
        MYSQL_ONLY=1
        shift
    elif [ $arg == "--psql" ]; then
        PSQL_ONLY=1
        shift
    elif [ $arg == "-h" ] || [ $arg == "--help" ]; then
        usage
        shift
    elif [ $arg == "--qa" ]; then
        QA_ONLY=1
        PSQL_ONLY=1
        MYSQL_ONLY=1
        shift
   elif [ $arg == "--qa" ] && [ $arg == "--mysql" ]; then
        QA_ONLY=1
        MYSQL_ONLY=1
        shift
   elif [ $arg == "--qa" ] && [ $arg == "--psql" ]; then
        QA_ONLY=1
        PSQL_ONLY=1
        shift
    elif [ $arg == "--" ]; then
        shift 
        break                                               
    fi                                                      
done                

Answer 1

If you can call getopt in bash, you can’t call getopt, it shouldn’t use long option name. use getopts instead of getopt.(below is a example)

#!/bin/bash

while getopts qm OPT
do
  case $OPT in
    q) opt_qa=1;;
    m) opt_mysql=1;;
  esac
done

if [ $opt_qa = 1 ]; then
  # do as qa
fi

if [ $opt_mysql = 1 ]; then
  # do as mysql
fi