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Home/ Questions/Q 6334425
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T18:39:22+00:00 2026-05-24T18:39:22+00:00

Here is code sample which reproduces my problem: template <typename myType> class Base {

  • 0

Here is code sample which reproduces my problem:

template <typename myType>
class Base {
public:
    Base() {}
    virtual ~Base() {}
protected:
    int myOption;
    virtual void set() = 0;
};

template <typename InterfaceType>
class ChildClass : public Base < std::vector<InterfaceType> >
{
public:
    ChildClass() {}
    virtual ~ChildClass() {}
 protected:
    virtual void set();
};

template <typename InterfaceType>
void ChildClass<InterfaceType>::set()
{
     myOption = 10;
}

My usage in main():

ChildClass<int> myObject;

I get the following error (gcc 4.4.3 on ubuntu):

‘myOption’ was not declared in this scope

If my ChildClass would be without new template parameter this would work fine, i.e.:

class ChildClass : public Base < std::vector<SomeConcreteType> >

Edit

I’ve managed to solve it, if my set method looks like:

Base<std::vector<InterfaceType> >::myOption = 10;

It works fine. Still though not sure why I need to specify all template parameters.

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  1. Editorial Team
    Editorial Team
    2026-05-24T18:39:24+00:00Added an answer on May 24, 2026 at 6:39 pm

    myOption is not a dependent name, i.e. it doesn’t depend on the template arguments explicitly so the compiler tries to look it up early. You must make it a dependent name:

    template <typename InterfaceType>
    void ChildClass<InterfaceType>::set()
    {
         this->myOption = 10;
    }
    

    Now it depends on the type of this and thus on the template arguments. Therefore the compiler will bind it at the time of instantiation.

    This is called Two-phase name lookup.

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