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Home/ Questions/Q 6882433
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T05:15:09+00:00 2026-05-27T05:15:09+00:00

Here is my code : char *name, name_log=log-; ——getting ‘name’ from user—– strcat(name_log, name);

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Here is my code :

char *name, name_log="log-";

——getting ‘name’ from user—–

strcat(name_log, name);
char ext[] = ".log";
strcat(name_log, ext);

What i need to end up with is name_log = “log-‘name’.log” but Im getting a segmentation fault error :((. What am I doing wrong and how can I fix it ? Thx

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  1. Editorial Team
    Editorial Team
    2026-05-27T05:15:10+00:00Added an answer on May 27, 2026 at 5:15 am

    For a start, if this is your code:

    char *name, name_log="log-";
    

    then name_log is a char, not a char pointer.

    Assuming that’s a typo, you cannot append to string literals like that. Modifications to string literals are undefined behaviour.

    For a variable sized string, as user appears to be, probably the safest option is to allocate another string large enough to hold the result, something like:

    char *name, *name_log = "log-", *ext = ".log";
    // Do something to allocate and populate name
    char *buffer = malloc (strlen (name_log) + strlen (name) + strlen (ext) + 1);
    if (buffer == NULL) {
        // Out of memory.
    } else {
        strcpy (buffer, name_log);
        strcat (buffer, name);
        strcat (buffer, ext);
        // Do something with buffer.
        free (buffer);
    }
    

    The malloc ensures you have enough space to do all the string operations safely, enough characters for the three components plus a null terminator.

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