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Home/ Questions/Q 516143
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:42:04+00:00 2026-05-13T07:42:04+00:00

Here is my code: class a(object): d=’ddd’ def __contains__(self): if self.d:return True b=a() print

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Here is my code:

class a(object):
    d='ddd'
    def __contains__(self):
        if self.d:return True
b=a()
print b.contains('d')  # error
print contains(b,'d')  # error

See also: Override Python's 'in' operator? for the corresponding how-to implementation question.

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:42:04+00:00Added an answer on May 13, 2026 at 7:42 am

    Like all special methods (with “magic names” that begin and end in __), __contains__ is not meant to be called directly (except in very specific cases, such as up=calls to the superclass): rather, such methods are called as part of the operation of built-ins and operators. In the case of __contains__, the operator in question is in — the “containment check” operator.

    With your class a as you present it (except for fixing your typo, and using True instead of true!-), and b as its instance, print 'x' in b will print True — and so will any other containment check on b, since b always returns True (because self.d, a non-empty string, is true).

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